(a) When testing distribution transformers, the number of units in the sample (m1) shall be in accordance with §429.47(a) and DOE shall perform the following number of tests:

(1) If DOE tests four or more units, it will test each unit once;

(2) If DOE tests two or three units, it will test each unit twice; or

(3) If DOE tests one unit, it will test that unit four times.

(b) DOE shall determine compliance as follows:

(1) Compute the mean (X1) of the measured energy performance of the n1 tests in the first sample as follows:

eCFR graphic er07mr11.150.gif

where Xi is the measured efficiency of test i.

(2) Compute the sample standard deviation (S1) of the measured efficiency of the n1 tests in the first sample as follows:

eCFR graphic er07mr11.151.gif

(3) Compute the standard error (SE(X1)) of the mean efficiency of the first sample as follows:

eCFR graphic er07mr11.152.gif

(4) Compute the sample size discount (SSD(m1)) as follows:

eCFR graphic er07mr11.153.gif

where m1 is the number of units in the sample, and RE is the applicable DOE efficiency when the test is to determine compliance with the applicable energy conservation standard, or is the labeled efficiency when the test is to determine compliance with the labeled efficiency value.

(5) Compute the lower control limit (LCL1) for the mean of

eCFR graphic er02my11.089.gif

(6) Compare the mean of the first sample (X1) with the lower control limit (LCL1) to determine one of the following:

(i) If the mean of the first sample is below the lower control limit, then the basic model is not compliant and testing is at an end.

(ii) If the mean is equal to or greater than the lower control limit, no final determination of compliance or noncompliance can be made; proceed to Step (7).

(7) Determine the recommended sample size (n) as follows:

eCFR graphic er07mr11.155.gif

Given the value of n, determine one of the following:

(i) If the value of n is less than or equal to n1 and if the mean energy efficiency of the first sample (X1) is equal to or greater than the lower control limit (LCL1), the basic model is in compliance and testing is at an end.

(ii) If the value of n is greater than n1, the basic model is not compliant. The size of a second sample n2 is determined to be the smallest integer equal to or greater than the difference n−n1. If the value of n2 so calculated is greater than 21−n1, set n2 equal to 21−n1.

(8) Compute the combined (X2) mean of the measured energy performance of the n1 and n2 units of the combined first and second samples as follows:

eCFR graphic er07mr11.156.gif

(9) Compute the standard error (SE(X2)) of the mean full-load efficiency of the n1 and n2 units in the combined first and second samples as follows:

eCFR graphic er07mr11.157.gif

(Note that S1 is the value obtained above in (2).)

(10) Set the lower control limit (LCL2) to,

eCFR graphic er07mr11.158.gif

where t has the value obtained in (5) and SSD(m1) is sample size discount determined in (4), and compare the combined sample mean (X2) to the lower control limit (LCL2) to determine one of the following:

(i) If the mean of the combined sample (X2) is less than the lower control limit (LCL2), the basic model is not compliant and testing is at an end.

(ii) If the mean of the combined sample (X2) is equal to or greater than the lower control limit (LCL2), the basic model is in compliance and testing is at an end.

[76 FR 12451, Mar. 7, 2011; 76 FR 24781, May 2, 2011]


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